expm1, expm1f, expm1l - exponential minus 1
Synopsis
Description
#include <math.h>double expm1(double x);
float expm1f(float x);
long double expm1l(long double x);
expm1(x) returns a value equivalent to exp (x) - 1. It is computed in a way that is accurate even if the value of x is near zero--a case where exp (x) - 1 would be inaccurate due to subtraction of two numbers that are nearly equal.
BSD, C99. The float and the long double variants are C99 requirements.
exp(3), log(3), log1p(3)
| EXPM1 (3) | 2002-07-27 |